# 832. Flipping an Image

## Easy

***

Given an `n x n` binary matrix `image`, flip the image **horizontally**, then invert it, and return *the resulting image*.

To flip an image horizontally means that each row of the image is reversed.

* For example, flipping `[1,1,0]` horizontally results in `[0,1,1]`.

To invert an image means that each `0` is replaced by `1`, and each `1` is replaced by `0`.

* For example, inverting `[0,1,1]` results in `[1,0,0]`.

 

**Example 1:**

<pre><code>Input: image = [[1,1,0],[1,0,1],[0,0,0]]
<strong>Output:
</strong> [[1,0,0],[0,1,0],[1,1,1]]
<strong>Explanation:
</strong> First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
</code></pre>

**Example 2:**

<pre><code>Input: image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
<strong>Output:
</strong> [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
<strong>Explanation:
</strong> First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
</code></pre>

&#x20;

**Constraints:**

* `n == image.length`
* `n == image[i].length`
* `1 <= n <= 20`
* `images[i][j]` is either `0` or `1`.